The Class 8 is an important year in a student’s life and Maharashtra State Board Maths is one of the subjects that require dedication, hard work, and practice. It’s a subject where you can score well if you are well-versed with the concepts, remember the important formulas and solving methods, and have done an ample amount of practice. Worry not! Home Revise is here to make your Class 8 journey even easier. It’s essential for students to have the right study material and notes to prepare for their board examinations, and through Home Revise, you can cover all the fundamental topics in the subject and the complete Maharashtra State Board Class 8 Maths Book syllabus.
Practice set 9.1 PAGE NO: 55
1. If marked price = Rs 1700, selling price = Rs 1540 then find the discount.
Solution:
Given:
Marked Price = Rs 1700
Selling Price = Rs 1540
By using the formula,
Selling price = Marked price – Discount
So,
Discount = Marked Price – Selling Price
Discount = 1700 – 1540
= Rs 160
∴ The discount is Rs 160.
2. If marked price = Rs 990 and percentage of discount is 10, then find the selling price.
Solution:
Given:
Marked price = Rs 990
discount = 10%
Let the percentage of discount be x
∴ x = 10%
By using the formula,
Discount = (Marked price × x) / 100
= (990 × 10) / 100
= Rs 99
Now,
Selling price = Marked price – Discount
= 990 – 99
= Rs 891
∴ The selling price is Rs 891.
3. If selling price = Rs 900. Discount is 20 %, then find the marked price.
Solution:
Given:
Selling Price = Rs 900
Discount = 20%
Now, let us consider the marked price as Rs x.
Given discount is 20% on the marked price.
Discount = 0.2x
By using the formula,
Selling Price = Marked Price – Discount
900 = x – 0.2x
900 = 0.8x
x = 900/0.8
= Rs 1125
∴ The marked price is Rs 1125.
4. The marked price of the fan is 3000 rupees. Shopkeeper gave 12% discount on it. Find the total discount and selling price of the fan.
Solution:
Given:
Marked Price = Rs 3000
Discount = 12%
Given discount is 12% on the marked price.
Discount = (12/100) × 3000
= Rs 360
Hence, the discount is Rs 360.
Now, by using the formula,
Selling Price = Marked Price – Discount
= 3000 – 360
= Rs 2640
∴ The selling price is Rs 2640.
5. The marked price of a mixer is 2300 rupees. A customer purchased it for Rs.1955. Find percentage of discount offered to the customer.
Solution:
Given:
Marked Price = Rs 2300
Selling Price = Rs 1955
By using the formula,
Discount = Marked Price – Selling Price
= 2300 – 1955
= Rs 345
Now, let us consider the percentage of discount as x.
Then,
x/100 = Discount/Marked Price
x/100 = 345/2300
x = (345 × 100)/2300
= 15
∴ The percentage of discount offered is 15%.
6. A shopkeeper gives 11% discount on a television set, hence the cost price of it is Rs. 22,250. Then find the marked price of the television set.
Solution:
Given:
Discount = 11%
Cost Price = Rs 22250
Let us consider the marked price be Rs x.
It is given discount is 11% on the marked price.
Discount = 0.11x
We also know the cost price is Rs 22250 after a discount of 11% on the marked price.
x – 0.11x = 22250
0.89x = 22250
x = 22250/0.89
= 25000
∴ The marked price is Rs 25000.
7. After offering discount of 10% on marked price, a customer gets total discount of 17 rupees. To find the cost price for the customer, fill in the following boxes with appropriate numbers and complete the activity.
Suppose, marked price of the item = 100 rupees
Solution:
8. A shopkeeper decides to sell a certain item at a certain price. He tags the price on the item by increasing the decided price by 25%. While selling the item, he offers 20% discount. Find how many more or less percent he gets on the decided price.
Solution:
Given:
price increase = 25%,
discount offered = 20%
Let the decided price be Rs 100
So, Increase in price = Rs 25
Shopkeeper marks the price = 100 + 25
= Rs 125
∴ marked price = Rs 125
Let the percentage of discount be x
x = 20%
Discount = (marked price × x) / 100
= (125 × 20) / 100
= 2500/100
= Rs 25
So, Selling price = Marked price – Discount
= Rs 125 – Rs 25
= Rs 100
If the decided price is Rs 100, then shopkeeper gets Rs 100.
∴ The shopkeeper gets neither profit nor loss than the decided price i.e. he gets 0% profit / loss.
Practice set 9.2 PAGE NO: 55
1. 
Solution:
Given:
Selling price of the books = Rs 4500
Rate of commission = 15%
By using the formula,
Commission = Commission Rate × Selling Price
Commission obtained = 15% of selling price
= (15/100) × (4500)
= 15 × 45
= 675 Rupees.
∴ The total commission obtained by John is Rs 675.
2. Rafique sold flowers worth Rs 15,000 by giving 4% commission to the agent. Find the commission he paid. Find the amount received by Rafique.
Solution:
Given:
Selling Price = Rs 15000
Commission rate = 4%
By using the formula,
Commission = Commission Rate × Selling Price
Commission = (4/100) × 15000
= Rs 600
Rafique paid a commission of Rs 600.
Amount received by Rafique = Selling Price – Commission
Amount received = 15000 – 600
= Rs 14400
∴ The amount received by Rafique is Rs 14400.
3. A farmer sold food grains for 9200 rupees through an agent. The rate of commission was 2%. How much amount did the agent get?
Solution:
Given:
Selling Price = Rs 9200
Commission rate = 2%
By using the formula,
Commission = Commission Rate × Selling Price
= (2/100) × 9200
= Rs 184
∴ The agent got a commission of Rs 184.
4. Umatai purchased following items from a Khadi –Bhandar.
(i) 3 sarees for 560 rupees each.
(ii) 6 bottles of honey for 90 rupees each.
On the purchase, she received a rebate of 12%. How much total amount did Umatai pay?
Solution:
Given:
Rebate = 15%
Cost of each saree = Rs 560
So, cost of 3 sarees = 3 × 560 = Rs 1680
Cost of each bottle = Rs 90
So, cost of 6 bottles = 6 × 90 = Rs 540
So, total cost of purchased items = 1680 + 540 = Rs 2220
Given rebate rate = 12%
By using the formula,
Rebate = Rebate Rate × Cost Price
= (12/100) × 2220
= Rs 266.40
Amount paid by Umatai = Total cost of purchase – Rebate
= 2220 – 266.40
= Rs 1953.60
∴ The total amount paid by Umatai is Rs 1953.60.
5.
Use the given information and fill in the boxes with suitable numbers.
Smt. Deepanjali purchased a house for Rs 7,50,000 from Smt. Leelaben through an agent. Agent has charged 2% brokerage from both of them.
Solution:
(1) Smt. Deepanjali paid = 7,50,000 × 2/100
= 7,500 × 2
= Rs 15,000 brokerage for purchasing the house.
(2) Smt. Leelaben paid brokerage of Rs 15,000
(3) Total brokerage received by the agent is = 15,000 + 15,000 = Rs 30,000
(4) The cost of house Smt. Deepanjali paid is = 7,50,000 + 15,000 = Rs 7,65,000
(5) The selling price of house for Smt.Leelaben is = 7,50,000 – 15,000
= Rs 7,35,000